Question 552701
How would I solve (b^4)^6*(b^2)^4 
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You can't solve it, it's not an equation.
You can simplify it some.
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(b^4)^6 --> when raising to a power, multiply the exponents
{{{(b^4)^6 = b^(4*6) = b^24}}}
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{{{(b^2)^4 = b^8}}}
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--> {{{b^24*b^8}}} when you multiply, add the exponents
--> {{{b^32}}}