Question 552589
<pre>
C(100,6)
-------- = .014465141
C(200,6)

Or you can look at it this way.  Suppose the gumballs come out one at a time.

The probability that the 1st one is green is {{{100/200}}} = {{{1/2}}}
The probability that the 2nd one is green is {{{99/199}}} 
The probability that the 3rd one is green is {{{98/198}}} = {{{49/99}}}
The probability that the 4th one is green is {{{97/197}}} 
The probability that the 5th one is green is {{{96/196}}} = {{{24/49}}}
The probability that the 6th one is green is {{{95/195}}} = {{{19/39}}}

Desired probability 
            
{{{1/2}}}{{{99/199}}}{{{49/99}}}{{{97/197}}}{{{24/49}}}{{{19/39}}} =

           {{{4}}}
          {{{cross(8)}}}
{{{1/cross(2)}}}{{{cross(99)/199}}}{{{cross(49)/cross(99)}}}{{{97/197}}}{{{cross(24)/cross(49)}}}{{{19/cross(39)}}} = {{{(97*4*19)/(199*197*13)}}} = {{{7372/509639}}} = .014465141 
            {{{13}}}





Edwin</pre>