Question 552588
There are 13 basketball players. All the players sit in a row on a bench. Determine the number of ways to arrange them such that the two youngest players sit together.
<pre>
Suppose the 13 basketball players are

A, B, C, D, E, F, G, H, I, J, K, L, M

Suppose L and M are the youngest.  Then we have to arrange either these
12 "things", where a "thing" is either a player or the pair of youngest
players, where L is left of M

A, B, C, D, E, F, G, H, I, J, K, (LM)

or these 12 "things" where L is right of M

A, B, C, D, E, F, G, H, I, J, K, (ML)

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In each case you can choose the left most thing 12 ways, the next one
11 ways, the next one 10, ways,... the next to the right one 2 ways and the
thing on the far right 1 way.  That's

12×11×10×9×8×7×6×5×4×3×2×1 = 12! = 479001600

But we must double this since we can have (LM) or (ML)

Answer =  479001600×2 = 958003200

Looks like you're exactly right!

Edwin</pre>