Question 552529
The unit digit of a two-digit number is one less than three times the tens digit. 
Let the number be 10t+u
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u = 3t-1
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The sum of the digits is 11. 
u + t = 11
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Find the number
Substitute for "u" and solve for "t":
3t-1+t = 11
4t = 12
t = 3
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Solve for "u":
u = 3t-1
u = 3*3-1 = 8
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Ans: The number is 10t+u = 38
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Cheers,
Stan H.
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