Question 552430
{{{(6&8/21)(K)}}}={{{13&1/3}}}
{{{134K/21}}}={{{40/3}}}
{{{K}}}={{{(40)(21)/(134)(3)}}}
{{{K}}}={{{cross(40)cross(21)/cross(134)cross(3)}}}
{{{K}}}={{{(20)(7)/67}}}
{{{K}}}={{{140/67}}}
{{{K}}}={{{2&6/67}}}