Question 552425

{{{(b+5)(6b-7)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(b)+5)(highlight(6b)-7)}}} Multiply the <font color="red">F</font>irst terms:{{{(b)*(6*b)=6*b^2}}}.



{{{(highlight(b)+5)(6b+highlight(-7))}}} Multiply the <font color="red">O</font>uter terms:{{{(b)*(-7)=-7*b}}}.



{{{(b+highlight(5))(highlight(6b)-7)}}} Multiply the <font color="red">I</font>nner terms:{{{(5)*(6*b)=30*b}}}.



{{{(b+highlight(5))(6b+highlight(-7))}}} Multiply the <font color="red">L</font>ast terms:{{{(5)*(-7)=-35}}}.



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So we have the terms: {{{6*b^2}}}, {{{-7*b}}}, {{{30*b}}}, {{{-35}}} 



{{{6*b^2-7*b+30*b-35}}} Now add every term listed above to make a single expression.



{{{6b^2+23b-35}}} Now combine like terms.



So {{{(b+5)(6b-7)}}} FOILs to {{{6b^2+23b-35}}}.



In other words, {{{(b+5)(6b-7)=6b^2+23b-35}}}.



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