Question 552013
1	y  	=	3	x	+	2				
Divide by 	1									
	y  	=	3.000	x	+	2				
Compare this equation with y=mx+b										
slope m =	3    									
										
The slope of a line perpendicular to the above line will be the negative reciprocal										m1*m2=-1										
The slope of the required line will be 	-1/3
													
m=	- 1/3	,point	(	1	,	-1	)			
Find b by plugging the values of m & the point in										
y=mx+b										
-1	=	-1/3	+	b						
b=	-2/3
									
m=	- 1/3									
The required equation is y  	=	-  1/ 3	x		-  2/ 3	


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1	y  	=	 2/3	x		-4				
Divide by 	1									
	y  	=	0.667	x	+	-4				
Compare this equation with y=mx+b										
slope m =	 2/3									
										
The slope of a line perpendicular to the above line will be the negative reciprocal										-1.5
m1*m2=-1										
										
										
m=	-3/2	,point	(	5	,	0	)			
Find b by plugging the values of m & the point in										
y=mx+b										
0	=	-15/2	+	b						
b=	15/2									
m=	-3/2									
The required equation is y  	=	-3/ 2	x	+	15/ 2			

		
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