Question 53726
A train leaves Roseville heading east at 6:00 am at 40 miles per hour. another eastbound train leaves on a parallel track at 7 am at 50 miles per hour. What time will it be when the two trains are the same distance away from Roseville?
:
Let t = time in hrs required by the 1st train which leaves at 6:00 am
:
The 2nd train leaves an hour later so it's time will be (t-1)
:
Dist = speed * time:
:
1st train dist = 2nd train dist
           40t = 50(t-1)
           40t = 50t - 50
        40t - 50t = -50
              -10t = -50
            t = -50/-10
            t = +5 hours
:
Add 5 hrs to 6:00 am; at 11:00 am they will be the same distance:
:
2nd train travels only 4 hours, 
:
check our solutions using distance: 40*5 = 50*4