Question 552041
{{{ x^2-2x-3= sqrt( 4 ) }}}
x^2-2x-3=2
x^2-2x  =5
x^2-2x+1=6 completing the square
(x-1)^2=6
x-1=+-sqrt(6) square root of each side.
x=1+sqrt(6), x=1-sqrt(6)
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Ed