Question 551692

{{{(5-6i)*(1-i)}}} Start with the given expression.



{{{(5)(1)+(5)(-i)+(-6i)(1)+(-6i)(-i)}}} FOIL.



{{{5-5i-6i+6i^2}}} Multiply.



{{{5-5i-6i+6(-1)}}} Replace {{{i^2}}} with {{{-1}}}. Note: {{{i^2=-1}}}.



{{{5-5i-6i-6}}} Multiply.



{{{-1-11i}}} Combine like terms.



So {{{(5-6i)*(1-i)=-1-11i}}}.



So the expression is now in standard form {{{a+bi}}} where {{{a=-1}}} and {{{b=-11}}}