Question 551620
Find the slope of the line passing through the points (5,-10) and (-1,-5).
						
Put the values of above points in the equation of straight line point-slope form				
m=(y2-y1)/(x2-x1)				
m=(-5-(-10))/(-1-5)				
m=(-5+10)/(-6)	
m=5/-6
m=-5/6	
Slope of the line = m = -5/6