Question 551512
let height be x ft
horizontal distance = x+5 ft

hypotenuse = 75

Pythagoras theorem states that		
		
Hypotenuse ^2= leg1^2+leg2^2		
		
Hypotenuse =	75	ft
leg1 = 	x	ft
leg2 = x+5
		
75^2=x^2+(x+5)^2
75^2=x^2+x^2+10x+25
2x^2+10x-5600=0
/2
x^2+5x-2800=0
Find the roots of the equation by quadratic formula						
					20	
a=	1	,b=	5	,c=	-2800	
						
b^2-4ac=	25	+	11200			
b^2-4ac=	11225					
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}						
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}						
{{{x1=(-12+21)/(2)}}}						
x1=(	-5	+	105.95	)/2		
x1=	50.47					
x2=(	-5	-105.95	) /	2		
x2= 	-55.47					
height = 50.47
horizontal length = (50.47+5)=55.47 ft