Question 551458
A (positive) profit is made when p(t) > 0. Hence we set


*[tex \LARGE -16t^2 + 64t - 48 > 0], for sake of simplicity I'll divide by -16 (remember to reverse the inequality sign)


*[tex \LARGE t^2 - 4t + 3 < 0]


*[tex \LARGE (t-3)(t-1) < 0]


At t = 1 or t = 3, p(t) = 0. Strangely, t = 2 is the only integer value that will return a positive amount of profit...