Question 551278
let a = the 10's digit
let b = the units
then
10a + b = "a certain two digit number
:
"A certain two digit number has a value that is three times the sum of it's digits."
10a + b = 3(a + b)
10a + b = 3a + 3b
10a - 3a = 3b - b
7a = 2b
:
" The units digit is one more than three times the tens digit."
b = 3a + 1
:
Substitute for b in the 1st equation
7a = 2(3a+1)
7a = 6a + 2
7a - 6a = 2
a = 2
;
I'll let you find b, check your solution in the 1st statement