Question 551290
A certain two digit number has a value that is seven more than six times the sum of it's digits. The tens digit is 3 more than the units digit. Find the number. Please help
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let t=ten's digit
let u=unit's digit
number=10t+u
t=u+3
..
10t+u=6(t+u)+7
10t+u=6t+6u+7
4t-5u=7
4(u+3)-5u=7
4u+12-5u=7
-u=-5
u=5
t=u+5=8
ans:
number=85