Question 551294
Mrs. John is five times as old as her son. Three years ago she was eight times as old as her son was then. Find each of their ages. Please help me solve this!!!
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At present:
let x=son's age
5x=mother's age
..
3 years ago:
x-3=son'age
5x-3=mother's age
..
5x-3=8(x-3) (mother 8 times as old as her son 3 years ago)
5x-3=8x-24
3x=21
x=7
5x=35
ans:
son's present age=7
mother's presentage=35