Question 551276
Let a = the larger number
Let b = the smaller
:
One number is five more than three times a smaller one.
a = 3b + 5
:
If four times the larger number is subtracted from twice the smaller one, the result is 0. 
2b - 4a = 0
replace a with (3b+5)
2b - 4(3b+5) = 0
2b - 12b - 20 = 0
-10b = 20
b = {{{20/(-10)}}}
b = -2
then
a = 3(-2) + 5
a = -6 + 5
a = -1
:
:
See if that checks out in the statement:
"four times the larger number is subtracted from twice the smaller one, the result is 0.
2(-2) - 4(-1) = 0
-4 + 4 = 0