Question 551221
Find the area of the region bounded by x = y3 , x+y=2 , y =0
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That's the area under y = x^3 from x=0 to x=1, and the x-axis, plus a triangle with vertices 
(1,0), (1,1) & (2,0).
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Under the curve:
Int(x^3)dx = {{{x^4/4}}}
Area = 1/4 sq unit
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The triangle is 1*1/2 = 1/2 sq unit
Total = 3/4 sq unit