Question 551186
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All of the possible spinner sections have odd numbers.  The sum of three odd numbers is odd.


Proof:


The *[tex \Large m]th odd number is *[tex \Large 2m\ -\ 1], the *[tex \Large n]th odd number is *[tex \Large 2n\ -\ 1], and the *[tex \Large p]th odd number is *[tex \Large 2p\ -\ 1], and the sum of these three arbitrary odd numbers is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (2m\ -\ 1)\ +\ (2n\ -\ 1)\ +\ (2p\ -\ 1)\ =\ 2(m\ +\ n\ +\ p\ -\ 1)\ -\ 1]


Which can be clearly seen to have a remainder of 1 when divided by 2, ergo the sum is odd.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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