Question 551191


{{{(12+q)(2-q)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(12)+q)(highlight(2)-q)}}} Multiply the <font color="red">F</font>irst terms:{{{(12)*(2)=24}}}.



{{{(highlight(12)+q)(2+highlight(-q))}}} Multiply the <font color="red">O</font>uter terms:{{{(12)*(-q)=-12*q}}}.



{{{(12+highlight(q))(highlight(2)-q)}}} Multiply the <font color="red">I</font>nner terms:{{{(q)*(2)=2*q}}}.



{{{(12+highlight(q))(2+highlight(-q))}}} Multiply the <font color="red">L</font>ast terms:{{{(q)*(-q)=-q^2}}}.



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So we have the terms: {{{24}}}, {{{-12*q}}}, {{{2*q}}}, {{{-q^2}}} 



{{{24-12*q+2*q-q^2}}} Now add every term listed above to make a single expression.



{{{24-10q-q^2}}} Now combine like terms.



So {{{(12+q)(2-q)}}} FOILs to {{{24-10q-q^2}}}.



In other words, {{{(12+q)(2-q)=24-10q-q^2}}}.