Question 551130
A certain two digit number has a value that is eight less than five times the sum of it's digits. The tens digit is 3 less than the units digit. Find the number.
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let t=ten's digit
let u=unit's digit
t=u-3
original 2-digit number=10t+u
..
10t+u=5(t+u)-8
10(u-3)+u=5t+5u-8
10u-30+u=5(u-3)+5u-8
10u-30+u=5u-15+5u-8
u=7
t=u-3=4
original 2-digit number=47