Question 551146
let the number is xy
The value of a certain two digit number is 4 more than six times the sum of it's digits.
so,xy=6(x+y)+4
If the digits are reversed, the resulting number is 18 less than the original number.
which means, yx=xy-18=6(x+y)+4-18=6(x+y)-14
here x,y values must be even numbers to satisfies the equation.
let us take the numbers randomly
let x=4,y=2,so xy=42 (in this problem x value must be greater because,yx=xy-18)

 yx=6(x+y)-14 = 6(4+2)-14 = 36-14=22 doesnot satisfies the condition
let x=6,y=2,so xy=62
yx=6(x+y)-14 = 6(6+2)-14 = 48-14=34 doesnot satisfies the condition

let x=6,y=4,so xy=64
yx=6(x+y)-14 = 6(6+4)-14 =60-14=46
46=46 satisfies the equation
so,original number is 64.