Question 551095
-x^2y^2/x^1/2y^0 = (-x^2y^2/x^1)(2Y^0)  (since,c/a/b=bc/a)
                 =(-x^2y^2/x)(2*1)      (since a^1=a,a^0=1)
                 =2*(-x^(2-1)*y^2)      (since a^p/a^q = a^(p-q))
                 =-2*(x^1*y^2)
                 =-2xy^2   --------->answer