Question 551002

Total number of possible committee = 16C3


i) number of possible committee having 3 boys =  10C3

probability = 10C3 /16C3


ii) number of possible committee having exactly 2 boys =  10C2* 6C1

probability = 10C2*6C1  /16C3



iii) number of possible committee having at least one  boy =  16C3 - 6C3 

probability = [ 16C3 - 6C3 ]/16C3




iv) number of possible committee having exactly 2 girls =  6C2* 10C1

probability = 6C2*10C1  /16C3



If any doubt, feel free to contact..