Question 550744
This is how it looks from my helicopter, flying low:
{{{drawing(300,300,-5,5,-5,5,
line(5,-4,-4,5), line(-5,-3.887,0,-1),line(0,-1,4,-5),
line(-5,4,-1.268,0.268), line(-5,-1.887,-1.268,0.268),
line(5,-5,0.634,-0.634), line(-5,-2.887,-0.634,-0.366),
red(arrow(5,-4.7,2,-1.7)),red(line(2,-1.7,0,0.3)),
red(arrow(0,0.3,-2,-0.854)),red(line(-2,-0.854,-5,-2.585)),
blue(arrow(-5,4.3,-3,2.3)),blue(line(-3,2.3,-0.888,0.188)),
blue(arrow(-0.888,0.188,-3,-1.031)),blue(line(-3,-1.031,-5,-2.185)),
green(arrow(0,0.3,-4,4.3)),green(arrow(-0.888,0.188,4,-4.7)),
locate(-4,4.8,A), locate(0,0.8,B), locate(-4,-1.7,C),
locate(4,-4.5,D), locate(-0.888,0.688,E), locate(-4.7,-1.8,F),
arrow(2,1,2,4), locate (1.9,4.5,N)
)}}} The motor home heading northwest follows the red path; the other one follows the blue path.
The motor home heading northwest changes its direction by the angle ABC (75.2°). The motor home heading southeast changes its direction by the angle DEF (to be found).
It looks very complicated looking this close up, but it is simpler than it seems. You would see how simple it is if you looked from a higher altitude. There are 2 groups of parallel lines. Seen from a higher altitude, each set of parallel lines would merge into one line, like this.
{{{drawing(300,300,-5,5,-5,5,
line(5,-5,-5,5),
line(-5,-2.887,0,0),
locate (0,0.7,B),
locate (0.2,0.3,E),
arrow(2,1,2,4),locate (1.9,4.5,N),
locate(-1.6,0.3,"75.2°"),locate(-2,2.3,A), locate(-2,-1.1,F),
locate(2,-2.2,D), locate(-2.7,-1,C)
)}}} Angles ABC and DEF are supplementary. They add up to 180°.
Angle DEF measures 180° - 75.2° = 104.8°
Disclaimer:I don't really own a helicopter, but I live close to the helicopter museum, which has fairs in which they offer helicopter rides for a very reasonable price (that I don't think I can afford, either).