Question 550872
The value of a certain two digit number is 9 times the sum of it's digits. If the digits are reversed, the resulting number is 63 less than the original number. 
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Let the number be 10t+u.
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Equations:
10t+u = 9(t+u)
10u+t = 10t+u-63
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Simplify each equation:
t = 8u
9t = 9u + 63
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Modify:
t = 8u
t = u + 7
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Solve for "u":
8u = u+7
u = 1
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Solve for "t":
t = 8u
t = 8
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Original Number: 10t+u = 81
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Cheers,
Stan H.
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