Question 550768
For the GCF problem, b^3 goes into both b^3 and b^4. Our GCF of 16 and 24 is 8
so our answer is 8b^3


2) 8a+16 just multiply the 8 by each term

3) x^2+2x-1

You can write the problem as 
xxxx+2*xxx-xx/xx
And cancel out two x's in each term