Question 550553
<pre>
Let A = log(8) and B = log(9)

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To get log(2):

log(8) = A

log(2³) = A

3log(2) = A

log(2) = {{{A/3}}}

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To get log(3):

log(9) = B

log(3²) = B

2log(3) = B

log(3) = {{{B/2}}}

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To get log(4)

log(4) = log(2²) = 2log(2) = 2({{{A/3}}}) = {{{(2A)/3}}}
 
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To get log(6)

log(6) = log(2×3) = log(2) + log(3) = {{{A/3}}} + {{{B/2}}}

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log(8) = A

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log(9) = B

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log(12) = log(4×3) = log(4) + log(3) = {{{(2A)/3}}} + {{{B/2}}}

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log(16) = log(8×2) = log(8) + log(2) = A + {{{A/3}}} = {{{(4A)/3}}}

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log(18) = log(9×2) = log(9) + log(2) = B + {{{A/3}}} 

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log(24) = log(8×3) = log(8) + log(3) = A + {{{B/2}}}

Edwin</pre>