Question 1132
 By factoring 
 x^3-12x^2+44x-48 = (x-4)(x-2)(x-6) = 0

 The roots are 2,4 or 6.
 Solution set {2,4,6}

 [or use synth. division]
  1-12 + 44 -48 (4
     +4 -32  +48
  ---------------
   1 -8 + 12 (2
     +2 - 12
  ---------------
   1 -6  0