Question 550651
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(1,5\right)]. So this means that {{{x[1]=1}}} and {{{y[1]=5}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(0,2\right)].  So this means that {{{x[2]=0}}} and {{{y[2]=2}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(2-5)/(0-1)}}} Plug in {{{y[2]=2}}}, {{{y[1]=5}}}, {{{x[2]=0}}}, and {{{x[1]=1}}}



{{{m=(-3)/(0-1)}}} Subtract {{{5}}} from {{{2}}} to get {{{-3}}}



{{{m=(-3)/(-1)}}} Subtract {{{1}}} from {{{0}}} to get {{{-1}}}



{{{m=3}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(1,5\right)] and *[Tex \LARGE \left(0,2\right)] is {{{m=3}}}