Question 550634
multiply (3+ 2i)(2-5i)7i
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Do the binomials:
(3+ 2i)(2-5i)
Do it the same as any binomial multiply.
(3+ 2i)(2-5i) = 3*(2-5i) + 2i*(2-5i)
= 6-15i + 4i-10i^2
i^2 = -1
= 6-15i + 4i+10
= 16 - 11i
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Multiply by 7i
7i*(16 - 11i) = 112i - 77i^2
i^2 is still = -1
= 112i + 77
= 77 + 112i