Question 550573
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The measure of the midsegment (the segment whose endpoints are the midpoints of the non-parallel sides of the trapezoid) of a trapezoid is the average of the  measures of the two parallel sides.


The two parallel sides are *[tex \Large \overline{AB}] and *[tex \Large \overline{DC}], so the average is *[tex \Large \frac{AB\ +\ DC}{2}] which, according to the givens is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{(x\ +\ 8)\ +\ 187}{2}]


And this average has to be equal to the given measure of the midsegment, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{(x\ +\ 8)\ +\ 187}{2}\ =\ 4x\ +\ 3]


Solve for *[tex \Large x].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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