Question 550531
Let {{{ L }}} = length
Let {{{ W }}} = width
given:
Perimeter = {{{ 50 }}} m
(1) {{{ L = 2W + 1 }}} m
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The formula for perimeter is
(2) {{{ P = 2W + 2L }}} 
Substitute (1) into (2)
(2) {{{ 50 = 2W + 2*( 2W + 1 ) }}}
(2) {{{ 50 = 2W + 4W + 2 }}}
(2) {{{ 6W = 48 }}}
(2) {{{ W = 8 }}} m
and, since
(1) {{{ L = 2W + 1 }}}
(1) {{{ L = 2*8 + 1 }}}
(1) {{{ L = 17 }}} m
The dimensions are 8 x 17 m2
check:
{{{ P = 2*8 + 2*17 }}}
{{{ P = 16 + 34 }}}
{{{ P = 50 }}} m