Question 550294
according to above it reads as shown below which i dont think u meant but its what you put down
{{{x-(3/2) = (6/x)-2}}} 
{{{x-(3/2)+2 = (6/x)}}} 
{{{x-(3/2)+(4/2) = (6/x)}}} 
{{{x(x+(1/2)) = (6/x)(x)}}} 
{{{(x^2+(1/2)x) = (6)}}} 
{{{x^2+(1/2)x-6=0}}} 
 *[invoke quadratic "x", 1, 1/2, -6]