Question 550397
Factor by grouping, if possible, and check
8a3 − 2a2 + 12a − 3
(8a^3 - 2a^2) + (12a - 3)
2a^2(4a - 1) + 3(4a - 1)
Factor out the (4a-1) to get:
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(4a - 1)(2a^2+3)
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Cheers,
Stan H.
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