Question 53633
<pre><font size = 3><b>Complete the ordered pairs so the each is a solution for the given equation. 
3x + 4y = 12 (0, ), ( ,3/4), ( ,0), (8/3, ).

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In an ordered pair the x-xoordinate is first and the y-coordinate is second.

If you are given the first coordinate and are asked to find the second one,
substitute the first coordinate for x in the equation and solve for y, and
put that in for the missing second coordinate.


If you are given the second coordinate and are asked to find the first one,
substitute the second coordinate for y in the equation and solve for x, and
put that in for the missing first coordinate.

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3x + 4y = 12 (0,  ) 

Here we are given the first coordinate, 0,  and are asked to find the 
second one, so we substitute 0 for x in the equation and solve for y:

3(0) + 4y = 12
   0 + 4y = 12
       4y = 12
        y = 12/4
        y = 3

and we put 3 in for the missing second coordinate and get (0, 3)

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3x + 4y = 12 (  , 3/4) 

Here we are given the second coordinate, 3/4, and are asked to find the 
first one, so we substitute 3/4 for y in the equation and solve for x:

3x + 4(3/4) = 12
     3x + 3 = 12
         -3   -3
-----------------
     3x     =  9
          x = 9/3
          x = 3

and we put 3 in for the missing first coordinate and get (3, 3/4)

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3x + 4y = 12 (  , 0) 

Here we are given the second coordinate, 0, and are asked to find the 
first one, so we substitute 0 for y in the equation and solve for x:

  3x + 4(0) = 12
     3x + 0 = 12
         3x = 12
          x = 12/3
          x = 4

and we put 4 in for the missing first coordinate and get (4, 0)

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3x + 4y = 12 (8/3,  ) 

Here we are given the first coordinate, 8/3,  and are asked to find the 
second one, so we substitute 8/3 for x in the equation and solve for y:

3(8/3) + 4y = 12
     8 + 4y = 12
    -8        -8
 -----------------   
         4y =  4
          y = 4/4
          y = 1

and we put 1 in for the missing second coordinate and get (8/3, 1)
Edwin</pre>