Question 550219
Let the width of sidewalk be x 															
..															
Length of garden =			15												
Width =			11												
															
Area =			165		M^2										
Area of sidewalk =			60	M^2											
Length of ground + sidewalk =							15	+	2	x					
width of ground + sidewalk = 				12+2x											
															
(15+2x	)(11+2x)-60=165
															

165+30x	+22x+4x^2-60=	165
4X^2+52	x-60=0					
Find the roots of the equation by quadratic formula														
	a=	4	b=	52	c=	-60									
	b^2-4ac=	2704	+	960											
	b^2-4ac=3664	
	{{{sqrt(	3664	)}}}=	60.53							
	{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}														
	{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}														
	x1=(	-52	+	60.53	)/	8									
	x1=	1.07													
	x2=(	-52	-60.53	) /	8										
	x2= 	-14.07													
	Ignore negative value														
width = 1.07 m