Question 53633
Ordered pairs are given as (x,y).
For (0,y), let x=0 and solve for y.
3x+4y=12
3(0)+4y=12
4y=12
4y/4=12/4
y=3
Your ordered pair is: (0,3)
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for (x,3/4)
Let y=3/4 and solve for x.
3x+4(3/4)=12
3x+12/4=12
3x+3=12
3x+3-3=12-3
3x=9
3x/3=9/3
x=3
Your ordered pair is: (3,3/4)
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for (x,0)
Let y=0 and solve for x.
3x+4(0)=12
3x=12
3x/3=12/3
x=4
Your ordered pair is: (4,0)
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for (8/3,y)
let x=8/3 and solve for y.
3(8/3)+4y=12
24/3+4y=12
8+4y=12
-8+8+4y=12-8
4y=4
4y/4=4/4
y=1
Your ordered pair is: (8/3,1)
Happy Calculating!