Question 550316
1) A BAG OF DIMES AND QUARTERS IS WORTH $3.55. THERE ARE FOUR MORE THAN DOUBLE THE NUMBER OF DIMES AS QUARTERS. HOW MANY OF THE COINS ARE DIMES?
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Value Equation: 10d + 25q = 355 cents
Quantity Eq:::: q = 2d+4
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Substitute for "q" and solve for "d":
10d + 25(2d+4) = 355
10d + 50d + 100 = 355
60d = 255
Comment: d is not a whole number;
The problem is inconsistent.
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2)THE PERIMETER OF A TRIANGLE IS 23 INCHES. THE LONGEST SIDE EXCEEDS THE SHORTER BY 7 INCHES WHILE THE THIRD SIDE IS TWICE THE SHORT SIDE. WHAT IS THE LENGTH OF THE LONGEST SIDE?
Let the shortest side be "x":
Longest = "x+7"
3rd side = 2x
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Equation:
x + 2x + x+7 = 23
4x = 16
x = 4 inches (shortest)
2x = 8 inches (3rd side)
x+7 = 11 inches (longest)
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3) TWICE A NUMBER LESS FIVE IS LESS THAN THE NUMBER LESS THREE. WHAT'S THE VALUE OF THE NUMBER? 
Equation:
2x-5 < x-3
x < 2
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4) THE SUM OF TWO NUMBERS IS 25, AND THEIR DIFFERENCE IS 9. WHAT ARE THE TWO NUMBERS? 
Equation:
x + y = 25
x - y = 9
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Add and solve for "x":
2x = 34
x = 17
Solve for "y":
x+y = 25
17 + y = 25
y = 8
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Cheers,
Stan H.
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