Question 53632
<p>Because you have two denominators here in fractions, you need to find the LCD.  In this case, it's 15 (3*5=15).  Now multiply both sides by 15: {{{15*6x-15*(1/5)-15*(2x/3)=15*3}}}.  Now expand the equation and we get {{{90x-3-10x=45}}}. Combining like terms we get {{{80x-3=45}}}, and then adding 3 to both sides yields {{{80x=48}}}.  Finally, divide both sides by 80 and we get {{{x=48/80}}}, which reduces to {{{x=3/5}}}.</p>
To check our work, substitute the value of x in the original equation, thusly: {{{6*(3/5)-1/5-(2(3/5))/3=3}}}.  Expanding gives us {{{18/5-1/5-2/5=3}}}, which reduces to {{{(18-1-2)/15=3}}}, which reduces still to {{{3=3}}}.  Because 3=3 is a true statement, that means our answer of {{{x=3/5}}} is correct!