Question 550184
In triangle ABC , angle B = 76 degrees , side a=45cm and side b=53cm . Find angle A
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The other tutor seemed to assume a right triangle.
If it's not:
Use the Law of Sines.
sin(A)/a = sin(B)/b
sin(A)/45 = sin(76)/53
sin(A) = 45*sin(76)/53
sin(A) =~ 0.823836
A =~55.47 degs