<PRE><B>Question 550129</B>
one side of the whiteboard is x + 4y inches, the other side should be x^2 + 4xy - 6y^2 inches
:
. . . x^2 + 4xy - 6y^2
. . . X. . . . . x + 4y
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. . . 4x^2y + 16xy^2 - 24y^3
. x^3 + 4x^2y - 6xy^2
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. x^3 + 8x^2y + 10xy^2 - 24y^3 = the area of the board
:
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