Question 550203
Train A   	80	mph						
Train B 	96	mph						
Train A   		04:20						
Train B 		04:35						
Difference in time=		00:15	=>	0.25	hours			
Train A   	will have covered	20	m 	before 	Train B 		starts	from station
catch up distance=		20	m 					
catch up speed =		96	-80	mph				
catch up speed =		16	mph					
Catchup time = catchup distance/catch up speed								
catch up time=		20	/	16				
catch up time=		1.25	hours	

Train B will catch up 1t 5.50 pm

m.ananth@hotmail.ca