Question 550137
<pre>
{{{(n+24)/n}}} = {{{n/n}}} + {{{24/n}}} = 1 + {{{24/n}}}

Therefore {{{(n+24)/n}}} will be an integer if and only if 24 is
evenly divisible by n.  Therefore the only integer values
n can have are 1,2,3,4,6,8,12, and 24, that is, the divisors of 24.
And the sum of the divisors of 24 is:

1+2+3+4+6+8+12+24 = 60

Edwin</pre>