Question 549966
A number is divisible by 5 if it ends in 5 or 0. Since zero is not an option, it must end in 5.

Also, we need to note that using the digits given, if we start with a 9, we will go over 9000 (because, again, 0 is not an option)

Now, assuming we can use each digit more than once,

for the first digit we have 4 options, for the next, 5 options, 5 options again (and the last digit just had one option)

So we get that there are 100 possibilities.