Question 547939
log3^(4x-7)=(1/9)
convert to exponential form: base(3) raised to log of number(1/9)=number(4x-7)
3^(1/9)=4x-7
1.1298=4x-7
4x=1.1298+7=8.1298
x=8.1298/4
x≈2.03245