Question 549923
HINT: Use the GROUPING METHOD to factor your polynomial of 4 terms. 
If you don't know this method, write back.  This is not linear algebra.


Here is your reply:

"Thank you for the hint.  I had already used the grouping method and I got
x^2(2x+3)-5(x+3) = 0 and I did not know where to go from there.  If that 2x wasn't there then I could have grouped (x+3)."

You did very well.  

Here is the factored form:

(x^2 - 5)(2x + 3)(x + 3) = THREE FACTORS = 0.


Now set each factor to equal zero and solve for x individually.


Can you take it from here?


Merry Christmas!