Question 549887
Let the smallest integer = {{{ n }}}
The next larger integer = {{{ n + 1 }}}
The 3rd larger integer = {{{ n + 2 }}}
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given:
{{{ n*(n+1) = n+ 2 + 194 }}}
{{{ n^2 + n = n + 196 }}}
{{{ n^2 = 196 }}}
{{{ n = sqrt(196) }}}
{{{ n = 14 }}}
{{{ n + 1 = 15 }}}
{{{ n + 2 = 16 }}}
The largest integer is 16
check answer:
{{{ n*(n+1) = n+ 2 + 194 }}}
{{{ 14*15 = 16 + 194 }}}
{{{ 210 = 210 }}}
OK