Question 549832
Let's let n be the smallest integer, meaning n+1 is the middle one and n+2 is the largest. 


From the question we can obtain the following inequalities:
{{{n+n+1>27}}}
{{{2n>27-1}}}
{{{2n>26}}}
{{{n>13}}}


and 
{{{n+1+n+2<39}}}
{{{2n+3<39}}}
{{{2n<39-3}}}
{{{2n<36}}}
{{{n<18}}}

So it doesn't matter what our integers are as long as {{{13<n<18}}}   (so n is either 14 15 16 or 17) and from there we can get the other two integers.  
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Hopefully this helps a bit! 
Romans 5:8