Question 549809

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(1,5\right)]. So this means that {{{x[1]=1}}} and {{{y[1]=5}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(6,4\right)].  So this means that {{{x[2]=6}}} and {{{y[2]=4}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(4-5)/(6-1)}}} Plug in {{{y[2]=4}}}, {{{y[1]=5}}}, {{{x[2]=6}}}, and {{{x[1]=1}}}



{{{m=(-1)/(6-1)}}} Subtract {{{5}}} from {{{4}}} to get {{{-1}}}



{{{m=(-1)/(5)}}} Subtract {{{1}}} from {{{6}}} to get {{{5}}}



So the slope of the line that goes through the points *[Tex \LARGE \left(1,5\right)] and *[Tex \LARGE \left(6,4\right)] is {{{m=-1/5}}}